Isosceles triangle abc contains angle bisectors segment bf, segment ad, and segment ce that intersect at x. triangle abc with diagonals bf, ad, and ec that intersect at point x if segment ba is congruent to segment bc and m∠bca = 46°, what is m∠cxa?

The measure of angle CXA is 134°

Step-by-step explanation:

* Lets explain how to solve the problem

- Triangle ABC is an isosceles triangle where AB = BC

∵ AB = BC

- The base angles in the isosceles triangle are congruent

∴ m∠BAC = m∠BCA

∵ m∠ BCA = 46° ⇒ given

∴ m∠ BAC = 46°

- The sum of the measures of the interior angles in any triangle is 180°

∵ m∠BAC + m∠BCA + m∠ABC = 180°

- Substitute the values of angle BAC and BCA in the equation above

∴ 46 + 46 + m∠ABC = 180

∴ 92 + m∠ABC = 180

- Subtract 92 from both sides

∴ m∠ABC = 88°

- BF , AD , CE are bisectors segments of angles B , A , C and they are

  intersected at point X

∵ CE bisects ∠BCA

∵ X ∈ CE

∴ m∠XCA = 1/2 m∠BCA

∴ m∠XCA = 1/2 (46) = 23°

∵ AD bisects ∠BAC

∵ X ∈ AD

∴ m∠XAC = 1/2 m∠BAC

∴ m∠XAC = 1/2 (46) = 23°

- In Δ AXC

∵ m∠XAC = 23° ⇒ proved

∵ m∠XCA = 23° ⇒ proved

∵ m∠CXA + m∠XAC + m∠XCA = 180° ⇒ interior angles of Δ

Substitute the values of angles XAC and XCA

∴ m∠AXC + 23 + 23 = 180

∴ m∠CXA + 46 = 180

- Subtract 46 from both sides

∴ m∠CXA = 134°

* The measure of angle CXA is 134°

134

Step-by-step explanation:

step-by-step explanation:

the answer to this question is 3/19

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