Suppose a statistics class contains five freshmen, ten sophomores, ten junior students, and ten senior students. randomly pick up 4 students from the class to form a study group. what is the probability that the study group contains exactly one freshman, one sophomore, one junior, and one senior?

The probability is 0.0955

Step-by-step explanation:

The number of ways in which we can select k elements from n elements in which the order is not important is given by combinations and it is calculated as:

So, the total number of ways in which we can select 4 students from the 35 in the statistics class are:

From this, the number of ways in which there are exactly one freshman, one sophomore, one junior and one senior are calculated as:

5C1 * 10C1 * 10C1 * 10C1 = 5,000

Because:

So, the probability is calculated as a division between the number of ways in which there are exactly one freshman, one sophomore, one junior and one senior and the total number of ways in which we can select 4 students from the 35 in the statistics class. This is:

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1

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