The lead common multiple of each set of numbers
2,6 4,5,10 3,5,7

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

the first option is the answer.

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i think da answer is

d.square root of 3