Apark has a grinkgo tree a dogwood tree and 2 blue spruce trees the blue spruce trees are 8 years old the grinkgo tree is 2 years less than three times the age of the dogwood tree the grinkgo tree is also half the sum of the ages of the dogwood tree and both if the blue spruce trees write and solve an equation to find the ages of the grinkgo and the dogwood trees.

The age of the grinkgo tree is 10 years old and the age of the dogwood tree is 4 years old

Step-by-step explanation:

Let

x -----> the age of the grinkgo tree

y -----> the age of the dogwood tree

z -----> the age of the blue spruce tree

we know that

------> equation A

----> equation B

substitute the value of z

-----> equation C

equate equation A and equation C and solve for y

Find the value of x (equation A or equation C)

therefore

The age of the grinkgo tree is 10 years old and the age of the dogwood tree is 4 years old

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!