Ann and carol are driving their cars along the same straight road. carolis located at x=2.4 mi at t=0 hand drives at a steady 36 mph. an n, who is traveling in the same direction, is located at x=0.0 mi at t=0.50 hand drives at a steady 50mph.

they will meet in 1.96h at x = 73 mi

Step-by-step explanation:

Ann: x=0.0 mi at t=0.50h v=50 mph

Carol: x=2.4 mi at t=0 v=36 mph

For Ann

S = S₀ + vt

0 = S₀ + 50.0.5

0 = S₀ + 25

S₀ = -25

∴ Sann = -25 + 50t

For Carol

S = S₀ + vt

Scarol = 2.4 + 36t

Sann = Scarol

-25 + 50t = 2.4 + 36t

50t - 36t = 2.4 + 25

14t = 27.4

t = 1.96 h

Scarol = 2.4 + 36t

Scarol = 2.4 + 36*1.96

Scarol = 2.4 + 36*1.96

Scarol = 73 mi

what is the question here

step-by-step explanation: