Asap the function graphed approximates the height of a rock, in meters, x seconds after it falls from a cliff
after about how many seconds is the rock 20 m above the ground
1.5 s
1.9s
2.2s
2.7s

The vertical numbers are the distance and the horizontal numbers are the time in seconds.

Look at where the line is located at the number 20.

It si between the 2 and the 3 on the horizontal line, but you can see it is closer to the 2 than it is the 3, so the time would be 2.2s

2.2 seconds

Step-by-step explanation:

The attached graph shows the height of a rock after it falls from a cliff. Let after t seconds the rock is 20 meters from the ground.

If the graph is not given we can calculate the time using the second equation of motion i.e.

Where

u is the initial speed of the rock

a is the acceleration of the rock

t is the time taken

Here, distance covered is in y axis and the time taken is in x axis. Approximately, at 2.2 seconds the rock is 20 meters above the ground. Hence, this is the required solution.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this