Atriangle has a bottom left angle of (x + 15) degrees and a bottom right angle of (x degrees). 1 parallel and horizontal line sits at the top point of the triangle. another parallel and horizontal line sits at the base of the triangle. the exterior angle to the bottom right angle of the triangle is (4 x minus 20) degrees. what is the value of x? x = 32 x = 36 x = 37 x = 40

    x = 40°

Option 4 is correct

Step-by-step explanation:

A triangle has a bottom left angle of (x + 15)° and a bottom right angle of x°

We are given two base angle of a triangle.

Therefore,  ∠ABC = (x + 15)° and ∠ACB = x°

One parallel and horizontal line sits at the top point of the triangle at Point A

Another parallel and horizontal line sits at the base of the triangle on side BC

Please have a look a attachment

The exterior angle to the bottom right angle of the triangle is (4 x - 20)°

Therefore, ∠ACX = (4x - 20)°

At point C, makes two angle on a straight line.

Both angles must be supplementary. It means sum of angles is 180°

∠ACB + ∠ACX  = 180°

   x° + (4x - 20)° = 180°

            5x - 20° = 180°

                     5x = 200°

                       x = 40°

Hence, The value of x is 40°

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x