If his ship hasn't already been hit, captain william has probability 1/3 of hitting the pirate ship. if his ship has been hit, captain william will always miss. if her ship hasn't already been hit, dread pirate emily has probability 1/7 of hitting the captain's ship. if her ship has been hit, dread pirate emily will always miss. if the captain and the pirate each shoot once, and the captain shoots first, what is the probability that the captain hits the pirate ship, but the pirate misses?

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)

mental cunning

explanation:

he is often referred to as a man of twists and turns

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

it is true

step-by-step explanation:

all the combinations add up i used   calculator