Find the equation of the line that passes through the point left (-9,12) and is perpendicular to the line y=3/2x-1/2. write the equation using the slope-intercept form.

The answer to your question is: y = -2/3 x + 18

Step-by-step explanation:

Data

Point = (-9, 12)

line   y = 3/2x -1/2     perpendicular

Process

The line must be perpendicular to the line given. Then,

slope is the line given = 3/2, we change it because the lines must be perpendicular ,

New slope         M =  -2/3

New line       y-y1 = m(x - x1)

                     y - 12 = -2/3 (x + 9)             Substitution

                   3( y - 12) = -2(x + 9)

                   3y - 36 = -2x - 18                 Simplify

                   3y = -2x - 18 + 36

                   3y = -2x + 18

                      y = -2/3 x+ 18                      Result

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.