Vector a has a magnitude of 6.00 units and is directed at 60° to the positive x-axis. vector b has a magnitude of 6.00 units and is directed at 120° to the positive x-axis. find the magnitude and direction of vector c such that a+b+c=0. place the three vectors so that one begins where the previous ends. what do you observe?

C has a magnitud of 10.4 units and is directed 270° from the positive x-axis

Step-by-step explanation:

As it shows on the attached picture, the xA and xB have equal magnitudes but opposite directions, therefore they cancel eachother out in the x-axis.

However, the yA and yB are equal in magnitud, but have the same direction. So, the create a total vector the is completely on the y-axis and it's magnitude is 2*(sin(60°)*6)=10.4 units.

In order for C to cancel this vector, it's magnitude also needs to be 10.4 units, but pointing the other way. Therefore, the angle needs to be 270° from the positive x-axis.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,