abcd is a square. p is a point inside the square. straight lines join points a and p, b and p, d and p, and c and p. triangle dpc is an equilateral triangle
jim makes the chart shown below to prove that triangle apd is congruent to triangle bpc:
statements justifications
in triangles apd and bpc; dp = pc sides of equilateral triangle dpc are equal
in triangles apd and bpc; ad = bc sides of square abcd are equal
in triangles apd and bpc; angle adp = angle bcp angle adc = angle bcd = 90° and
angle adp = angle bcp = 90° − 60° =
30°
triangles apd and bpc are congruent sss postulate
what is the error in jim's proof?
a. he writes dp = pc instead of dp = pb.
b. he writes ad = bc instead of ad = pc.
c. he assumes the measure of angle adp and angle bcp as 30° instead of 45°.
d. he assumes that the triangles are congruent by the sss postulate instead of sas postulate.