Consider the line y=-5/9x+6
find the equation of the line that is parallel to this line and passes through the point (9, -3).
find the equation of the line that is perpendicular to this line and passes through the point (9, -3

See below in bold.

Step-by-step explanation:

Use the point-slope form of a straight line

y - y1 = m(x - x1)

Here m = -5/9 , x1 = 9 and y1 = -3:, so

y - -3 = -5/9(x - 9)

y + 3 = -5/9x + 5

y = -5/9x + 2  is the equation parallel to the given line.

The  line perpendicular to the given line will have a slope of - 1 / -5/9

= 9/5 so its equation is

y  + 3 = 9/5(x - 9)

y = 9/5x - 81/5 - 3

y = 9/5x - 96/5 .

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !