Ineed a baseball is thrown at an angle of 20º relative to the ground at a speed of 25.0 m/s. if the ball was caught 50.0 m from the thrower, how long was it in the air? (1 point)
how high did the baseball travel before beginning it's descent?

Step-by-step explanation:

Let's split the analysis on two components, horizontal and vertical.

Supposed no air resistence, the horizontal movement is given by the expression . Since it travels 50 m, solving for you get .

The vertical movement is given by the expression , where is the gravitational acceleration. The highest point is reached when the vertical velocity () is zero, or at

Please note that the number are heavily approximated, do plug yours in a calculator

saving = more money

step-by-step explanation:

if you have 100 bucks, and you want to buy a candy bar, even if you have one at home, if you choose not to buy it, you save.

~courtney