, n=0,1,2,..
p(n): 1 + 2 + 2^2 + 2^3 + . . + 2n = 2n+1 - 1, n = 0, 1, 2, . .
Mathematics, 14.09.2019 10:20 Nobleufia
given the proposition,
p(n): 1 + 2 + 2^2 + 2^3 + . . + 2n = 2n+1 - 1, n = 0, 1, 2, . .
find the values of:
p(0)
p(1)
p(2)
p(n+1)
Answers: 3
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given the proposition,
p(n): 1 + 2 + 2^2 + 2^3 + . . + 2n = 2n+1 - 1, n = 0, 1, 2, . .
p(n): 1 + 2 + 2^2 + 2^3 + . . + 2n = 2n+1 - 1, n = 0, 1, 2, . .
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