Cost data
regular time labor cost per hour $10
overtime time labor cost per hour $15
subcontracting cost per unit (labor only) $80
back order cost per unit per period $20
inventory holding cost per unit per period $10
hiring cost per employee $500
firing cost per employee $400
capacity data
beginning workforce 40 employees
beginning inventory 0 units
beginning back orders 0 units
production standard per unit (hours) 2 hours of labor per unit
regular time available per period (hours) 160 hours per period per employee
overtime time available per period (hours) 30 hours per period per employee
demand data
period 1 3,920 units period 5 3,800 units
period 2 2,480 units period 6 4,340 units
period 3 2,200 units period 7 4,820 units
period 4 3,280 units period 8 4,600 units
develop a level aggregate plan using inventory and back orders (data given above).
(a) what is the production rate per period? no overtime is to be used. what is the required workforce level and how many workers are hired or fired at the beginning of period 1? what is the maximum ending inventory and when does it occur? what is the maximum amount of back orders and when does it occur? what is the total cost? what is the cost per unit?

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

=====================================

part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

=====================================

part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.

f . i can go whenever i feel like it bc it is confidential meaning only i would know how much i deposited besides the bank and they wouldnt care bc when you make a deposit you are using their services which means they are using there competition and gaining more customers

and if they dont well then thats less customers for them in a less profitable way

plz mark brainliest