What substitution should be used to rewrite 16
+ 1)-3 = 0 as a quadratic equation?
u = (x3)
u = (x3 + 1)
u= (x3 + 1)2
u=(x3 + 1)3

range is infinite on both x and y axis positive and negative

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

∡ eia and ∡ kij are congruent

step-by-step explanation: