Atelemarketer makes a sale on 25% of his calls. if he makes 300 calls in a night, what is the probability that he will make more than 70 sales but less than 90 sales?

0.7258

Step-by-step explanation:

Given : A telemarketer makes a sale on 25% of his calls.

i.e. p=0.25

He makes 300 calls in a night, i.e. n=300

Let x be a random variable that represents the number of calls make in night.

To convert the given binomial distribution to normal distribution we have :-

Now, using , the z-value corresponds to x= 70 :-

The z-value corresponds to x= 90 :-

By using the standard normal distribution table for z, the probability that he will make more than 70 sales but less than 90 sales:-

Hence, the probability that he will make more than 70 sales but less than 90 sales= 0.7258

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

idk lol xd

step-by-step explanation:

ez do it yourself lazy