Social sciences alcohol abstinence the harvard school of public health completed a study on alcohol consumption on college campuses. they concluded that 20.7% of women attending all-women colleges abstained from alcohol, compared to e6% of women attending coeducational colleges. approximately 4.7% of women college students attend all-women schools. source: harvard school of public health. (a) what is the probability that a randomly selected female student abstains from alcohol? (b) if a randomly selected female student abstains from alcohol, what is the probability she attends a coedücational colege?

a) There is a 6.69% probability that a randomly selected female student abstains from alcohol.

b) If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

Step-by-step explanation:

This is a probability problem:

We have these following probabilities:

-20.7% of a woman attending an all-women college abstaining from alcohol.

-6% of a woman attending a coeducational college abstaining from alcohol.

-4.7% of a woman attending an all-women college

- 100%-4.7% = 95.3% of a woman attending a coeducational college.

(a) What is the probability that a randomly selected female student abstains from alcohol?

is the probability of a woman attending an all-women college being chosen and abstaining from alcohol. There is a 0.047 probability of a woman attending an all-women college being chosen and a 0.207 probability that she abstain from alcohol. So:

is the probability of a woman attending a coeducational college being chosen and abstaining from alcohol. There is a 0.953 probability of a woman attending a coeducational college being chosen and a 0.06 probability that she abstain from alcohol. So:

So, the probability of a randomly selected female student abstaining from alcohol is:

There is a 6.69% probability that a randomly selected female student abstains from alcohol.

(b) If a randomly selected female student abstains from alcohol, what is the probability she attends a coedücational colege?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

Here:

What is the probability of a woman attending a coeducational college, knowing that she abstains from alcohol.

It can be calculated by the following formula:

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

We have the following probabilities:

is the probability of a woman from a coeducational college being chosen. So

is the probability of a woman abstaining from alcohol, given that she attends a coeducational college. So

is the probability of a woman abstaining from alcohol. From a),

So, the probability that a randomly selected female student attends a coeducational college, given that she abstains from alcohol is:

If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: