According to the partial construction shown, what is the next step in constructing a line perpendicular to a point on the line?
place compass at point d, and draw an arc that intersects the arc above df.
place compass at point f, and drawn arc that intersects the arc above de.
place compass at point p, and draw an arc above df
place compass at point p, and draw an arc below df

Place compass at point D, and draw an arc that intersects the arc above

DF ⇒ 1st answer.

Step-by-step explanation:

* Lets revise how to construct a perpendicular line to a line from point

 on the line

- Place your compass pin on P and draw an arc of any size below

 the line that crosses it at two points label them D and F

- Enlarge the distance of the compass and place the compass pin

 on point F and make a small arc above the line

- Without changing the distance of the compass, place the compass

 pin on point D and draw another arc intersects the arc from point F

- Use a straightedge to join the intersection point of the two small

 arcs with point P

* Now lets find the next steps in the drawing

∵ The face of the arc above DF is front to point F

∴ This arc is drawn from point F

∴ The next step is "Place compass at point D, and draw an arc that

   intersects the arc above DF"

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

no because mercury has a density of 13.6 grams per centimeter squared while gold has 19.32 grams centimeter squared

step-by-step explanation: