The number of vibrations n n per second of a nylon guitar string varies directly with the square root of the tension t t and inversely with the length l l of the string. if the tension is 256 256 kilograms when the number of vibrations per second is 15 15 and the length is 0.6 0.6 meters, find the tension when the length is 0.3 0.3 meters and the number of vibrations is 12 12 .

Step-by-step explanation:

We know that:

: The number of vibrations per second of the nylon guitar string.

: Tension.

: The length of the string.

Since    varies directly with the square root of the   and inversely with  , the equation has the following form:

Where "k" is the constant of variation.

Knowing that when and , , we can find the value of "k":

Finally, in order to find the tension when the length is 0.3 meters and the number of vibrations is 12, you need to substitute these values and the value of "k" into and solve for :

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

there are infinitely many solutions.