‼️‼️solve by substitution {2p-3r=6
{-2p+3r=-6 all these problems w work shown r due in the morning pls

#7: (p, r) = (0, -2) #8: (z,w) = z, + z), ∈R  #9: (c,d) = (3,3) #10: (u,x) ∈∅ #11: (a,b) = (-1, 2) #12:

Step-by-step explanation:

#7

Solve for 2p

2p - 3r = 6

2p = -6 -3r

substitute the given value of 2p into equation 2p - 3r = 6

-6 - 3r - 3r = 6

solve for r

r= -2

substitute value of r in equation

2p = -6 - 3x (-2)

solve for p

p=0

solution is ordered pair (p,r) = (0, -2)  

#8

Solve for w

w= + z

substitute the given value of w into equation

6 ( + z) - 8z = 16

solve for z

z ∈ R

The statement is true for any value of z and w that satisfy both equations from the system. Therefore, the solution is in parametric form.

(z,w) = z, + z)

#9

Solve for c

c + d = 6

c = d

substitute the given value of c into equation c + d = 6

d + d = 6

solve for d

d=3

substitute value of d in equation

c=3

solution is ordered pair (c,d) = (3,3)

#10

Solve for u

u= 3-2x

substitute the given value of c into equation

2 (3-2x) +4x = -6

solve for x

x ∈∅

Since the system has no solution for x the answer is  

(u,x) ∈∅

#11

Solve for b

b= 5+3a

substitute the value of b into equation

3a + 5 + 3a+ b = -1

solve for a

a= -1

substitute the value of a into equation

b= 5 + 3x (-1)

solve for b

b=2

solution is ordered pair (a, b) = (-1, 2)

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step-by-step explanation:

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right