Acash register at a store contains $66 bills. there are 6 more $5 bills than $10 bills. the number of $1 dollar bills is three times more the number of $10 dollar bills. how many bills of each kind are there?

There are 8 $5 bills, 2 $10 bills, and 6 $1 bills.

Step-by-step explanation: If you have 6 more $5 bills than the number of $10 bills, that means you have at least 6 to start off with. This also means you have at least 1 $10 bill. If you have 1 $10 bill, then you have 3 $1 bills as well. Adding those bills up, you get $43. From here, you know you need $3 more. Meaning you have to add another $10 bill. Since you added another $10 bill, you have to equal out the $5 bills.

So if you know you have 2 $10 bills and 6 $1 bills, you can determine that you need 8 $5 bills to complete the set.

2 $10 = $20

8 $5 = $40

6 $1 = $6

$20 + $40 + $6 = $66

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: