Find three consecutive integers whose sum is 441

146, 147 and 148

Step-by-step explanation:

Let the three integers be x, x+1, and x+2.

(they are consecutive)

Now, we are given that their sum is 441.

So,

(x) + (x+1) + (x+2) = 441

3x + 3 = 441

3x = 438

x = 438/3

x = 146

Thus, the integers are:

x = 146

x+1 = 147

x+2 = 148

Please mark Brainliest if this helps!

the answer is d. (1.2, -4.7) on edgn

hope this !

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: