Maya has 3 times as many dimes as nickels. she has 4 more quarters than nickels. if she has a total of $9.40, how many of each type of coin does she have?

 nickels = 14, dimes = 42, quarters = 18

Step-by-step explanation:

Let n represent nickels which has a value of $0.05

Let d represent dimes which has a value of $0.10

Let q represent quarters which has a value of $0.25

It is given that:

                       n = n

                      d = 3n

                      q = n + 4

and their total value is $9.40    ⇒     n + d + q = $9.40

Use substitution to find the quantity of nickels:

.05(n) + .10(3n) + .25(n + 4) = 9.40

 5n    +  10(3n) +   25(n+4)   = 940           multiplied by 100

 5n    +   30n   +  25n + 100 = 940          distributed

                            60n + 100 = 940          added like terms

                            60n           = 840          subtracted 100

                                 n           = 14            divided by 60

n = 14

                d = 3n

                   = 3(14)

                   = 42

                                       q = n + 4

                                          = (14) + 4

                                           = 18

answer: 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

step-by-step explanation: