30 points and brainliest for best answer! if you can!
the figure shows triangle abc and line segment pq, which is parallel to bc: (picture attached)
part a: is triangle abc similar to triangle apq? explain using what you know about triangle similarity. (5 points)
part b: which line segment on triangle apq corresponds to line segment bc? explain your answer. (3 points)
part c: which angle on triangle apq corresponds to angle b? explain your answer. (2 points)

part 1-similar triangle states that the two triangles are similar if their corresponding angles are congruent and the corresponding sides are in proportion. therefore, we can say that the triangle abc is similar to triangle apq.

part 2-in ∆abc, pq is a line segment intersecting ab at p and ac at q such that pq || bc and pq divides the two similar triangles is used and is equal to the ratio of their squares of the corresponding sides. pq is parallel to bc and pq divides the triangle into two parts

part 3-aob apq (corresponding angles)

step-by-step explanation:

part a :

the triangles are similar through sas (side - angle - side)

part b :

line pq corresponds to line bc since pq and bc are parallel from the triangles.

part c :

angle p corresponds to angle b via triangle similarity

hope this

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .