Match each polynomial expression to its additive inverse

   (1, 2, 3, 4) matches (A, C, B, D)

Step-by-step explanation:

The additive inverse of a term is formed by changing the sign. The additive inverse of the polynomial is formed by changing the sign of every term.

If we call the expressions on the left (top-to-bottom) 1, 2, 3, 4, and those on the right A, B, C, D, then the match-up in this presentation of the question is ...

  1 - A

  2 - C

  3 - B

  4 - D

YMMV if the expressions are mixed differently

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

the f

last graph i believe

step-by-step explanation:

worked it out i believe