![a)\quad \sqrt[3]{27}\quad = \sqrt[3]{3\cdot3\cdot3}\quad =\large\boxed{3}\\\\b)\quad \sqrt[3]{-64}\quad = \sqrt[3]{-4\cdot-4\cdot-4}\quad =\large\boxed{-4}](/tpl/images/0226/7198/4911b.png)
Ijust need the answers you don’t have to explain for number 4
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Mathematics, 10.09.2019 09:10 lauraleemartinez
Ijust need the answers you don’t have to explain for number 4
Answers: 1
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