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Mathematics, 10.09.2019 01:20 kassidy49

Fix an alphabet Ļƒ. we define the notion of an awesome language recursively as follows. ā€¢ āˆ… is awesome; ā€¢ {a} for each a āˆˆ Ļƒ is awesome; ā€¢ if l1 and l2 are awesome, then l1 āˆŖ l2 is awesome; ā€¢ if l1 and l2 are awesome, then l1l2 is awesome; so an awesome language is any language that can be constructed by starting from the base cases and applying the recursive rules a finite number of times (hopefully it is clear which ones above correspond to the base cases and which ones correspond to the recursive rules). we define the notion of a super awesome language recursively as follows. ā€¢ āˆ… is super awesome; 2 ā€¢ {a} for each a āˆˆ Ļƒ is super awesome; ā€¢ if l1 and l2 are super awesome, then l1 āˆŖ l2 is super awesome; ā€¢ if l1 and l2 are super awesome, then l1l2 is super awesome; ā€¢ if l is super awesome, then lāˆ— is super awesome. 1. give a simple characterization for the set of all awesome languages. briefly justify your answer. a detailed argument is not needed. 2. is the set of all awesome languages the same as the set of all super awesome languages? briefly justify your answer using part (a). 3. for a function f : Ļƒ ā†’ Ļƒāˆ— and a language l āŠ† Ļƒāˆ—, define the language lf = {f(a1)f(a2)Ā·Ā·Ā·f(ak) : for all i, ai āˆˆ Ļƒ, and a1a2 āˆˆ l}. prove that for any f : Ļƒ ā†’ Ļƒāˆ—, if l is super awesome, then so is lf .

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Fix an alphabet Ļƒ. we define the notion of an awesome language recursively as follows. ā€¢ āˆ… is awesom...
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