On a coordinate plane, a curved line crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 0.25). the line exits the plane at (negative 2, negative 6) and (2, 6). which statement is true about the end behavior of the graphed function? as the x-values go to positive infinity, the function's values go to negative infinity. as the x-values go to zero, the function's values go to positive infinity. as the x-values go to negative infinity, the function's values are equal to zero as the x-values go to positive infinity, the function's values go to positive infinity.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the olimpics is not going to wokk out

step-by-step explanation:

where is the graph

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