Valeria is ordering medals for her school's track meet. company a charges $4.50 for each medal and a one-time engraving fee of $40. company b charges $6.50 for each medal and a one-time engraving fee of $20. which inequality can be used to find x, the least number of medals that can be ordered so that the total charge for company a is less than the total charge for company b? a) 4.5 + 40x < 6.5 + 20x b) 4.5 + 40x > 6.5 + 20x c) 4.5x + 40 < 6.5x + 20 d) 4.5x + 40 > 6.5x + 20

4.5x + 40 < 6.5x + 20

C is correct

Step-by-step explanation:

Valeria is ordering medals for her school's track meet.

Let total charge be $y and number of medals be x

#Company A charges $4.50 for each medal and a one-time engraving fee of $40.

 y = 4.5x + 40

#Company B charges $6.50 for each medal and a one-time engraving fee of $20.

 y = 6.5x + 20

The least number of medals that can be ordered so that the total charge for Company A is less than the total charge for Company B

Company A < Company B

   4.5x + 40 < 6.5x + 20

              2x > 20

                x > 10

Hence, The least value of x is 10 and inequality "  4.5x + 40 < 6.5x + 20 "

sine

step-by-step explanation:

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!