equation 1: m = 8 + 2n
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Mathematics, 21.11.2019 23:31 benjaminmccutch
The work of a student to solve a set of equations is shown:
equation 1: m = 8 + 2n
equation 2: 3m = 4 + 4n
step 1:
β3(m) = β3(8 + 2n) [equation 1 is multiplied by β3.]
3m = 4 + 4n [equation 2]
step 2:
β3m = β24 β 6n [equation 1 in step 1 is simplified.]
3m = 4 + 4n [equation 2]
step 3:
β3m + 3m = β24 β 6n + 4n [equations in step 2 are added.]
step 4:
0 = β24 β 2n
step 5:
n = β12
in which step did the student first make an error?
step 4
step 3
step 2
step 1
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Answers: 2
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The work of a student to solve a set of equations is shown:
equation 1: m = 8 + 2n
equation 1: m = 8 + 2n
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