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Mathematics, 21.11.2019 23:31 benjaminmccutch

The work of a student to solve a set of equations is shown:

equation 1: m = 8 + 2n
equation 2: 3m = 4 + 4n

step 1:
βˆ’3(m) = βˆ’3(8 + 2n) [equation 1 is multiplied by βˆ’3.]
3m = 4 + 4n [equation 2]

step 2:
βˆ’3m = βˆ’24 βˆ’ 6n [equation 1 in step 1 is simplified.]
3m = 4 + 4n [equation 2]

step 3:
βˆ’3m + 3m = βˆ’24 βˆ’ 6n + 4n [equations in step 2 are added.]

step 4:
0 = βˆ’24 βˆ’ 2n

step 5:
n = βˆ’12

in which step did the student first make an error?

step 4

step 3

step 2

step 1

ansver
Answers: 2

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The work of a student to solve a set of equations is shown:

equation 1: m = 8 + 2n
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