One line passes through the points (-7,5)
(−7,5) and (-1,-3) another line passes through points (0,3) and (3,-1)
are the lines perpendicular, parallel or neither ?

Prependicular

Step-by-step explanation:

Since you have 2 points of a line you can find the gradient of each line using (y2-y1)/(x2-x1) or change in y divided by change in x. For line one this is (-3-5)/(-1+7) = -8/6 = -4/3

For line two this is (-1-3)/(3-0) = -4/3

Since they have the same gradients they are in fact parallel

Perpendicular lines will have the negative recpriocal of each other gradient.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316