The vertex form of the equation of a horizontal parabola is given by x=\frac{1}{4}p(y-k)^2+h. where (h, k) is the vertex (6,4)

Find the equation of the ellipse with the following properties. the ellipse with foci at (0, 6) and (0, -6); y-intercepts (0, 8) and (0, -8).edit: the answer is x^2 over 28 + y^2 over 64 = 1