In a set of 24 cards, each card is numbered with a different positive integer from 1 to 24. one card will be drawn at random from the set. what is the probability that the card drawn will have either a number that is divisible by both 2 and 3 or a number that is divisible by 7 ?

Step-by-step explanation:

Considering that the set has 24 cards on it, numbered from 1 to 24 inclusive, it means that the total number of cases is 24. Now, we have to find the number of favorable outcomes.

In the interval 1 to 24 inclusive, :

Numbers divisible by 2 => 2 4 6 8 10 12 14 16 18 20 22 24

Numbers divisible by both 2 and 3 => 6 12 18 24

Which means that there are 4-favorable outcomes for this scenario.

In the interval 1 to 24 inclusive, :

Numbers divisible by 7 => 7 14 21

Which means that there are 3-favorable outcomes for this scenario.

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step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35

step-by-step explanation:

mean or average is 40.6