Correct answers only !
on a residential single lane road there was a wreck that backed up traffic for 5 miles. 80% of the traffic consists of cars and 20% of the traffic consists of trucks. the average distance between vehicles is 3 feet. the average length of a car is 13.5 feet and the average length of a truck is 20 feet. estimate how many vehicles are stuck in the traffic jam.
(hint: there are 5280 feet in 1 mile.)
a. 853 vehicles
b. 1510 vehicles
c. 2103 vehicles
d. 2320 vehicles

Option B.

Step-by-step explanation:

Length of the traffic has been given as 5 miles or 26400 feet (5×5280)

Let the number of cars in the traffic = x

Since average length of the car = 13.5 feet

So, length of traffic because of cars = 13.5x feet

Distance between the vehicle = 3 feet

Distance between x cars = 3x feet

Length of the traffic by cars = 80% of 26400

                                              = 21120 feet

Therefore, length of the traffic by cars = length of cars + distance between them

21120 = 13.5x + 3x

21120 = 13.5x + 3x

21120 = 16.5x

16.5x = 21120

x = 1280 cars

Let the number of trucks in the traffic = y

Length of each truck = 20 feet

Length of the traffic by the trucks = 20y feet

Distance between the trucks = 3y feet

Total length by trucks = 20y + 3y = 23y

Since length of the traffic by trucks is = 20% of 26400

                                                              = 5280 feet

Therefore, 5280 = 23y

y =

y = 230

Total number of vehicles = x + y = 1280 + 230

= 1510

Option B is the answer.

income. 10x+1300

expenses 3x+(1800+1500)

expenses 3x+3300

to break even:

income = expense,

10x + 1300 = 3x + 3300,

solve for x.

step-by-step explanation:

mark brainliest