Virus a will damage the system with probability 0.3. independently of it, virus b will damage the system with probability 0.5. independently of a and b, virus c will damage the system with probability 0.6. what is the probability that the system will be damaged (by at least one of the viruses)?

0.86.

Step-by-step explanation:

Probability (None of the viruses will do any damage) = (1 - 0.3)(1-0.5)(1-0.6)

= 0.14.

Therefore the probability that at least one will do damage = 1 - 0.14 = 0.86.

because its not ur topic and its not for is for homework not that.

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d