See explanation
Step-by-step explanation:
1. To determine whether the ordered pair is the solution to the inequality, just substitute the coordinates of the ordered pair into the inequality
![y-2x+y\g\le 4](/tpl/images/0224/4103/1d74c.png)
A. For the ordered pair (-2,-3),
![x=-2, y=-3](/tpl/images/0224/4103/4e6f4.png)
Thus,
![-3-2\cdot (-2)+(-3)\le 4\\ \\-3-4-3\le 4\\ \\-3-7\le 4](/tpl/images/0224/4103/d40e3.png)
This option is true, because -3>-7 and -7≤4
B. For the ordered pair (0,-4),
![x=0, y=-4](/tpl/images/0224/4103/42ccc.png)
Thus,
![-4-2\cdot 0+(-4)\le 4\\ \\-4-4\le 4](/tpl/images/0224/4103/5735f.png)
This option is false, because -4=-4 (not -4>-4)
C. For the ordered pair (1,5),
![x=1, y=5](/tpl/images/0224/4103/08519.png)
Thus,
![5-2\cdot 1+5\le 4\\ \\5-2+5\le 4\\ \\53\le 4](/tpl/images/0224/4103/244ab.png)
This option is true, because 5>3 and 3≤4
D. For the ordered pair (1,3),
![x=1, y=3](/tpl/images/0224/4103/3a10e.png)
Thus,
![3-2\cdot 1+3\le 4\\ \\3-2+3\le 4\\ \\31\le 4](/tpl/images/0224/4103/e405e.png)
This option is true, because 3>1 and 1≤4
2. The inequality
is equivalent to the system of two inequalities
![\left\{\begin{array}{l}-12x+2yy\\ \\-12x+2y\ge -32x+2\end{array}\right.\Rightarrow \left\{\begin{array}{l}-12x+y0\\ \\20x+2y\ge 2\end{array}\right.](/tpl/images/0224/4103/45ed7.png)
Plot the dotted line
and shade the upper region. Plot the solid line
and shede the right part. The intersection of these two regions is the solution set to the inequality
(see attached diagram)
![Asap 1.which ordered pair is a solution to the system of inequalities? {y> −2x+y≤4 (−2, −3) (0,](/tpl/images/0224/4103/6a880.jpg)