In 1990, the st. louis metropolitan area had an average of
82 x 10 to the negative 6th power g/m cubed of pollutants in the air. how many grams of pollutants were there in 2 x 10 cubed m cubed of air?
step by step

answer: (3,11) is your answer.

hey there! : )

4y < -4

we need to isolate y. we can do this by simply dividing both sides by 4.

4y ÷ 4 > -4 ÷ 4

simplify.

y > -1

5 - y > 0

once again, we need to isolate y, so we can start off by subtracting 5 from both sides.

5 - y - 5 > 0 - 5

simplify.

-y > -5

divide both sides by -1.

** remember that when dividing any side by a negative, you must switch the sign! **

-y ÷ -1 < -5 ÷ -1

simplify.

y < 5

~hope i ! ~