If an optical telescope focusing light of wavelength 550 nm has a per- fectly ground mirror, what would the minimum mirror diameter have to be so that the telescope could resolve a jupiter-size planet around our nearest star, alpha centauri, which is about 4.3 light- years from earth? (consult appendix f.)

diameter = 197.35 m

Step-by-step explanation:

given data

wavelength = 550 nm = 550× m

light year = 4.3

to find out

diameter D

solution

we know 1 light year have = 9.46 × m

so 4.30 light year = 40.678× m

and jupiter diameter is = 1.38 × m

now we find first angular resolution

that is = diameter / distance

so angular resolution = 1.38 ×  /  40.678×

angular resolution = 3.40 ×

so diameter formula is

diameter = 1.22 × wavelength / angular resolution

diameter = 1.22 × 550 ×  / 3.40 ×

diameter = 197.35 m

answer: plz give a pic and answer choices so i can answer!

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)