On a coordinate plane, a line goes through (negative 3, 2) and (0, 1). a point is at (3, 4). what is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)? y = –one-thirdx + 5 y = –one-thirdx + 3 y = 3x + 2 y = 3x − 5

Step-by-step explanation:

step 1

Find the slope of the given line

we have

(-3,2) and (0,1)

The slope m is

step 2

Find the slope of the line perpendicular to the given line

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of its slopes is -1)

so

The slope is

step 3

Find the equation of the line in point slope form

we have

----> equation in point slope form

Convert to slope intercept form

80

step-by-step explanation: