Find three odd integers such that the sum of the first, two times the second, and 3 times the third is70

9, 11, 13

Step-by-step explanation:

Let x, y, and z represent the odd integers:

x + 2y + 3z = 70

You need another clue to answer this question.  Let's assume they are consecutive odd integers.  Then: y = x + 2 and z = x + 4

Use substitution and solve for x:

x + 2(x + 2) + 3(x + 4) = 70

x  + 2x + 4  + 3x + 12  = 70

                    6x + 16   = 70

                    6x           = 54

                      x           =  9

y = x + 2                                  z = x + 4

  = 9 + 2                                    = 9 + 4

  =    11                                       =    13

So, the three consecutive odd integers are: 9, 11, & 13