Mathematics, 03.09.2019 19:20 payshencec21
Part a: if k is a constant, show that a general (one-parameter) solution of the differential equation dx/dt = kx^2 is given by x(t) = 1/(c-kt), where c is an arbitrary constant. part b: determine by inspection a solution of the initial value problem dx/dt = kx^2, x(0) = 0.
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Part a: if k is a constant, show that a general (one-parameter) solution of the differential equati...
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