If the sin 90° is 1, then the cos °=

The required value of Cos0° = 1 .

Given that,

The value sin90° = 1

We have to find,

The value of Cos0° is.

According to the question,

In a right triangle, the sine of one acute angle, A, equals the cosine of the other acute angle, B.

The cosine of any acute angle is equal to the sine of its complement. Sine and cosine are called "cofunctions",

Where the sine or cosine function. of any acute angle equals its cofunction of the angle's complement.

Sin = Cos( 90- x )

Where x = 0

Then,

Cos(90-x)° = cos(90-90)° = cos0°

And the value of cos0° is 1

Cos0° = 1

Hence, The required value of  Cos0° = 1 .

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If the sin 90° is 1, then the cos 0° = 1

Step-by-step explanation:

Given data:

= 1;

Step 1:

By the trigonometric identities

Sin x = Cos (90 - x)

Step 2:

From the given data we know X as 90. So substitute the 90 in the place of X.

Sin x = Cos (90 - x)

Then by putting x = 90°  

Step 3:

= Cos (90 - 90)

= Cos 0° (As we know Cos 0° = 1)

it could 14.28 but if its not that one then it has to be the 17 one. hope this ! : )

step-by-step explanation: