Someone me and do not just write anything explain you . use the information provided to write the vertex form equation of each parabola.

y= -2x^2-12x-28 i ended up with (6,-64) is that correct? and remember to add 28 to both sides first zzz sone hlp me

Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c

the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating

y=-2x^2-12x-28
a=-2
b=-12

xvalue of vertex is -(-12)/(2*-2)=12/-4=-3

x value of vertex is -3

plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10

yvalue is -10
x value is -3

vertex is (-3,-10)

Logical equivalent of the give question is its contrapositive