Afirm works 7 days a week. every employee must work exactly 3 full days and 4 half-days each week. a half-day can be either morning or afternoon, and two half-days cannot be held on the same day. a) how many possible different weekly schedules are there? 560 expected 560

  a)  560 (as you know)

Step-by-step explanation:

There are 7C3 = 35 ways to choose 3 full-time days from 7.

There are 2^4 = 16 ways to choose a half-day each day from the remaining 4 days.

The total number of possible schedules is ...

  35×16 = 560

nCk = n!/(k!(n-k)!)

7C3 = 7·6·5/(3·2·1) = 7·5 = 35

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6