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Mathematics, 21.12.2019 19:31 ashiteru123

The work of a student to solve a set of equations is shown:

equation a: y = 4 βˆ’ 2z
equation b: 4y = 2 βˆ’ 4z

step 1: βˆ’4(y) = βˆ’4(4 βˆ’ 2z) [equation a is multiplied by βˆ’4.]
4y = 2 βˆ’ 4z [equation b]
step 2: βˆ’4y = 4 βˆ’ 2z [equation a in step 1 is simplified.]
4y = 2 βˆ’ 4z [equation b]
step 3: 0 = 6 βˆ’ 6z [equations in step 2 are added.]
step 4: 6z = 6
step 5: z = 1

in which step did the student first make an error?
step 1
step 3
step 4
step 2

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Answers: 2

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The work of a student to solve a set of equations is shown:

equation a: y = 4 βˆ’ 2z
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