Which is equivalent to (9 y squared minus 4 x)(9 y squared + 4 x), and what type of special product is it? 81 y superscript 4 baseline minus 16 x squared, a perfect square trinomial 81 y superscript 4 baseline minus 16 x squared, the difference of squares 81 y superscript 4 baseline minus 72 x y squared minus 16 x squared, a perfect square trinomial 81 y superscript 4 baseline minus 72 x y squared minus 16 x squared, the difference of squares

Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.

Step-by-step explanation:

We need to solve:

(9y^2 -4x)(9y^2+4x)

Finding the product:

9y^2(9y^2+4x) -4x(9y^2+4x)

81y^4+36y^2x-36y^2x-16x^2

81y^4 - 16x^2

Type of Special product

The product is differences of square because

81y^4 = (9y^2)^2

and 16x^2 = (4x)^2

So, 81y^4 - 16x^2 =  (9y^2)^2 - (4x)^2

Hence Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

the correct answer is 5 6 and 7