Margaret is planning a wedding reception. she wants to spend less than her budget of $5,838, and margaret has already spent $2,618. the meal price per guest is $28. how many guests, x, can margaret invite to the reception and stay under budget?
select the number line that includes the largest number of guests margaret can invite without exceeding her budget.

155 guest

Step-by-step explanation:

5838-2618=3220

3220÷$28=155

The situation can be modeled by a linear inequality of the form px + q < r, where p is the cost per guest, q is the amount of money already spent, and r is the budget.

Set up an inequality and solve.

px + q < r

$26x +  $2,110 < $4,996

$26x < $4,996 - $2,110

$26x < $2,886

x < 111

Therefore, Margaret must invite less than 111 guests to stay under her budget

*cough cough one above me is wrong*

its a straight line parallel to the time axis

step-by-step explanation:

duck you