He slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -x + 6. what is the point-stopetom
of the equation for this line?
y-3= 2 (x + )
y + 3 = 2 (x-8)
y + 8 = 2 (x-3)
–8= 2 (x + 3)

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

your answer   is c

step-by-step explanation:

the answer i believe is 27 units.

step-by-step explanation:

step-by-step explanation:

(3rd option) - c