Asoftware company uses two quality assurance (qa) checkers x and y to check an application for bugs. x misses 11% of the bugs and y misses 13%. assume that the qa checkers work independently.
(a) what is the probability (as a %) that a randomly chosen bug will be missed by both qa checkers
(b) if the program contains 1,000 bugs, what number of bugs can be expected to be missed? (round your answer to the nearest integer.)

Given :  X misses 11% of the bugs and Y misses 13%.

To Find : a)What is the probability (as a %) that a randomly chosen bug will be missed by both QA checkers

b)If the program contains 1,000 bugs, what number of bugs can be expected to be missed?

Solution:

Probability of missing bugs by QA X = 11% = 0.11

Probability of missing bugs by QA Y = 13% = 0.13

So,the probability that a randomly chosen bug will be missed by both QA checkers  =

Now we are given that there are 1000 bugs

No. of Bugs can be expected to be missed =

                                                                      =

So, 15 bugs can be expected to be missed

answer: e 9, 5.75

step-by-step explanation:

step 1

find the variation ab in the x coordinate

delta x=(x2-x1)=10-> 8 units

find the variation ab  in the y coordinate 

delta y=(y2-y1)=6-> 2 units

step 2

find the coordinates point c

  x coordinate 

cx=ax+delta x*2/> cx=2+8*(2/> cx=3

  y coordinate 

cy=ay+delta y*2/> cy=4+2*(2/> cy=4.25

the coordinates of point c are (3,4.25)

step 3

find the coordinates point d

  x  coordinate 

dx=ax+delta x*4/> dx=2+8*(4/> dx=4

  y  coordinate 

dy=ay+delta y*4/> dy=4+2*(4/> dy=4.5

the coordinates of point d are (4, 4.5)

step 4

find the coordinates point e

  x  coordinate 

ex=ax+delta x*4/> ex=2+8*(6/> ex=5

  y  coordinate 

ey=ay+delta y*4/> ey=4+2*(6/> ey=4.75

the coordinates of point e are (5, 4.75)

step 5

find the coordinates point f

  x  coordinate 

fx=ax+delta x*4/> fx=2+8*(8/> fx=6

  y  coordinate 

fy=ay+delta y*4/> fy=4+2*(8/> fy=5

the coordinates of point f are (6,5)

step 6

find the coordinates point g

  x  coordinate 

gx=ax+delta x*4/> gx=2+8*(10/> gx=7

  y  coordinate 

gy=ay+delta y*4/> gy=4+2*(10/> gy=5.25

the coordinates of point g are (7,5.25)

step 7

find the coordinates point h

  x  coordinate 

hx=ax+delta x*4/> hx=2+8*(12/> hx=8

  y  coordinate 

hy=ay+delta y*4/> hy=4+2*(12/> hy=5.5

the coordinates of point h are (8,5.5)

step 8

find the coordinates point i

  x  coordinate 

ix=ax+delta x*4/> ix=2+8*(14/> ix=9

  y  coordinate 

iy=ay+delta y*4/> iy=4+2*(14/> iy=5.75

the coordinates of point i are (9,5.75)

- r3ktforgood ☕

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.